What are the solutions to the equation u^2+2u+1=0 ?

The solutions to the equation u^2+2u+1=0 are u=-1

Find the zeros of u^2+2u+1=0

The zeros of u^2+2u+1=0 are u=-1

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u^{2} + 2 u + 1 = 0

u = - 1

Solution steps

u^{2} + 2 u + 1 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 1 = 0

u_{1, 2} = \frac{- 2 \pm 0}{2 \cdot 1}

u = \frac{- 2}{2 \cdot 1}

\frac{- 2}{2 \cdot 1} = - 1

u = - 1

The solution to the quadratic equation is:

u = - 1

\frac{5 - x}{2} - 2 = \frac{1 - x}{2} - \frac{2 ( x + 1 )}{3}

(x - 3)^{2} (12 - 3 x) > 0

\frac{8 ^{- 6}}{4 ^{- 6}}

0 < \frac{1}{3} x < π

x^{2} - 2 x = 0

What are the solutions to the equation u^2+2u+1=0 ?
The solutions to the equation u^2+2u+1=0 are u=-1
Find the zeros of u^2+2u+1=0
The zeros of u^2+2u+1=0 are u=-1