What are the solutions to the equation 5y^2+2=-7y ?

The solutions to the equation 5y^2+2=-7y are y=-2/5 ,y=-1

Find the zeros of 5y^2+2=-7y

The zeros of 5y^2+2=-7y are y=-2/5 ,y=-1

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5 y^{2} + 2 = - 7 y

y = - \frac{2}{5}, y = - 1

Decimal Notation

y = - 0.4, y = - 1

Solution steps

5 y^{2} + 2 = - 7 y

Move

7 y

to the left side

5 y^{2} + 2 + 7 y = 0

Write in the standard form

a x^{2} + b x + c = 0

5 y^{2} + 7 y + 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 5 \cdot 2}{2 \cdot 5}

7^{2} - 4 \cdot 5 \cdot 2 = 3

y_{1, 2} = \frac{- 7 \pm 3}{2 \cdot 5}

Separate the solutions

y_{1} = \frac{- 7 + 3}{2 \cdot 5}, y_{2} = \frac{- 7 - 3}{2 \cdot 5}

y = \frac{- 7 + 3}{2 \cdot 5} : - \frac{2}{5}

y = \frac{- 7 - 3}{2 \cdot 5} : - 1

The solutions to the quadratic equation are:

y = - \frac{2}{5}, y = - 1

y^{2} + 22 = 38

4 x^{2} = 2 x + 11

5^{\frac{2}{3}} \cdot 5^{\frac{4}{3}}

3 = \frac{2 x + 19}{5}

m^{2} + 16 m + 40 = 0

What are the solutions to the equation 5y^2+2=-7y ?
The solutions to the equation 5y^2+2=-7y are y=-2/5 ,y=-1
Find the zeros of 5y^2+2=-7y
The zeros of 5y^2+2=-7y are y=-2/5 ,y=-1