What are the solutions to the equation 4n^2-4n-24=0 ?

The solutions to the equation 4n^2-4n-24=0 are n=3,n=-2

Find the zeros of 4n^2-4n-24=0

The zeros of 4n^2-4n-24=0 are n=3,n=-2

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4 n^{2} - 4 n - 24 = 0

n = 3, n = - 2

Solution steps

4 n^{2} - 4 n - 24 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 ( - 24 )}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 (- 24) = 20

n_{1, 2} = \frac{- ( - 4 ) \pm 20}{2 \cdot 4}

Separate the solutions

n_{1} = \frac{- ( - 4 ) + 20}{2 \cdot 4}, n_{2} = \frac{- ( - 4 ) - 20}{2 \cdot 4}

n = \frac{- ( - 4 ) + 20}{2 \cdot 4} : 3

n = \frac{- ( - 4 ) - 20}{2 \cdot 4} : - 2

The solutions to the quadratic equation are:

n = 3, n = - 2

\frac{4}{3} \cdot \frac{3}{2}

n^{2} + 2 n - 24 = 0

\frac{x}{x - 8} > 0

4 x (x + 1) - 7 (x + 1)^{2}

lo g_{3} (9)

What are the solutions to the equation 4n^2-4n-24=0 ?
The solutions to the equation 4n^2-4n-24=0 are n=3,n=-2
Find the zeros of 4n^2-4n-24=0
The zeros of 4n^2-4n-24=0 are n=3,n=-2