What is the answer to (3y+5)/2-(3y+2)/5 = 3/10 ?

The answer to (3y+5)/2-(3y+2)/5 = 3/10 is y=-2

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(3y+5)/2-(3y+2)/5 = 3/10

\frac{3 y + 5}{2} - \frac{3 y + 2}{5} = \frac{3}{10}

y = - 2

Solution steps

\frac{3 y + 5}{2} - \frac{3 y + 2}{5} = \frac{3}{10}

Multiply by LCM

5 (3 y + 5) - 2 (3 y + 2) = 3

Expand

5 (3 y + 5) - 2 (3 y + 2) : 9 y + 21

9 y + 21 = 3

Move

21

to the right side

9 y = - 18

Divide both sides by

9

y = - 2

12 y - 4 = 15 y + 8

15 y = 25 y^{2}

(∣ x + 4 ∣^{2} - 25) (x^{2} - 9) \leq 0

3 (x + 4) = 18

- 4 ∣ 1 - x ∣ < - 16

What is the answer to (3y+5)/2-(3y+2)/5 = 3/10 ?
The answer to (3y+5)/2-(3y+2)/5 = 3/10 is y=-2
Solve for y: (3y+5)/2-(3y+2)/5 = 3/10
The solution is y=-2