What are the solutions to the equation 25v^2-20v+4=0 ?

The solutions to the equation 25v^2-20v+4=0 are v= 2/5

Find the zeros of 25v^2-20v+4=0

The zeros of 25v^2-20v+4=0 are v= 2/5

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25 v^{2} - 20 v + 4 = 0

v = \frac{2}{5}

Decimal

v = 0.4

Solution steps

25 v^{2} - 20 v + 4 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 25 \cdot 4}{2 \cdot 25}

(- 20)^{2} - 4 \cdot 25 \cdot 4 = 0

v_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 25}

v = \frac{- ( - 20 )}{2 \cdot 25}

\frac{- ( - 20 )}{2 \cdot 25} = \frac{2}{5}

v = \frac{2}{5}

The solution to the quadratic equation is:

v = \frac{2}{5}

\frac{a + 4}{3} - \frac{a}{7} = \frac{a + 7}{5}

3 (x + 1)^{3} + 81 (x - 1)^{3}

\frac{6 a ^{5} b ^{7}}{- 2 a ^{3} b ^{7}}

4 x = - 2

∣ (x + 2) (x + 2) ∣ < 2 (2 - x)

What are the solutions to the equation 25v^2-20v+4=0 ?
The solutions to the equation 25v^2-20v+4=0 are v= 2/5
Find the zeros of 25v^2-20v+4=0
The zeros of 25v^2-20v+4=0 are v= 2/5