What is c/4+c/(10)>= (7c)/(20)-1/2 ?

The solution to c/4+c/(10)>= (7c)/(20)-1/2 is True for all c

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

c/4+c/(10)>= (7c)/(20)-1/2

\frac{c}{4} + \frac{c}{10} \geq \frac{7 c}{20} - \frac{1}{2}

True for all c

Interval Notation

(- \infty, \infty)

Solution steps

\frac{c}{4} + \frac{c}{10} \geq \frac{7 c}{20} - \frac{1}{2}

Move

\frac{7 c}{20}

to the left side

0 \geq - \frac{1}{2}

Therefore, the solution is

True for all c

- 7 y \leq 14

- 45 d^{2} + 4 d - 1 = 0

∣ - 2 x ∣ = 8

∣ 7 x - 6 ∣ \leq 29

2 - 5

What is c/4+c/(10)>= (7c)/(20)-1/2 ?
The solution to c/4+c/(10)>= (7c)/(20)-1/2 is True for all c