What are the solutions to the equation 5x^2-3x=2x^2+x ?

The solutions to the equation 5x^2-3x=2x^2+x are x= 4/3 ,x=0

Find the zeros of 5x^2-3x=2x^2+x

The zeros of 5x^2-3x=2x^2+x are x= 4/3 ,x=0

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5 x^{2} - 3 x = 2 x^{2} + x

x = \frac{4}{3}, x = 0

Decimal Notation

x = 1.33333 \dots, x = 0

Solution steps

5 x^{2} - 3 x = 2 x^{2} + x

Move

x

to the left side

5 x^{2} - 4 x = 2 x^{2}

Move

2 x^{2}

to the left side

3 x^{2} - 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 4)^{2} - 4 \cdot 3 \cdot 0 = 4

x_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 3}, x_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 3}

x = \frac{- ( - 4 ) + 4}{2 \cdot 3} : \frac{4}{3}

x = \frac{- ( - 4 ) - 4}{2 \cdot 3} : 0

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = 0

2 x - 10 = 4 \cdot (x - 3)

∣ 4 x - 8 ∣ < 12

4 x^{2} - 8 x - 2 = 0

8 b + 5 = 133

\frac{- 1 - ( \frac{- 9}{5} )}{2 - 1}

What are the solutions to the equation 5x^2-3x=2x^2+x ?
The solutions to the equation 5x^2-3x=2x^2+x are x= 4/3 ,x=0
Find the zeros of 5x^2-3x=2x^2+x
The zeros of 5x^2-3x=2x^2+x are x= 4/3 ,x=0