What are the solutions to the equation -4x^2+12x+14=0 ?

The solutions to the equation -4x^2+12x+14=0 are x=-(-3+sqrt(23))/2 ,x=(3+sqrt(23))/2

Find the zeros of -4x^2+12x+14=0

The zeros of -4x^2+12x+14=0 are x=-(-3+sqrt(23))/2 ,x=(3+sqrt(23))/2

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- 4 x^{2} + 12 x + 14 = 0

x = - \frac{- 3 + 23}{2}, x = \frac{3 + 23}{2}

Decimal Notation

x = - 0.89791 \dots, x = 3.89791 \dots

Solution steps

- 4 x^{2} + 12 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 4 ) \cdot 14}{2 ( - 4 )}

1 2^{2} - 4 (- 4) \cdot 14 = 423

x_{1, 2} = \frac{- 12 \pm 4 23}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 12 + 4 23}{2 ( - 4 )}, x_{2} = \frac{- 12 - 4 23}{2 ( - 4 )}

x = \frac{- 12 + 4 23}{2 ( - 4 )} : - \frac{- 3 + 23}{2}

x = \frac{- 12 - 4 23}{2 ( - 4 )} : \frac{3 + 23}{2}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 23}{2}, x = \frac{3 + 23}{2}

(x - 2 i) (x + 2 i)

6 i - 8

(\frac{( n + 1 ) ( n + 2 )}{2})^{2}

5 + 2 x = 21

6 x^{2} - 5 x - 17 = 0

What are the solutions to the equation -4x^2+12x+14=0 ?
The solutions to the equation -4x^2+12x+14=0 are x=-(-3+sqrt(23))/2 ,x=(3+sqrt(23))/2
Find the zeros of -4x^2+12x+14=0
The zeros of -4x^2+12x+14=0 are x=-(-3+sqrt(23))/2 ,x=(3+sqrt(23))/2