What are the solutions to the equation 16r^2-8r+1=0 ?

The solutions to the equation 16r^2-8r+1=0 are r= 1/4

Find the zeros of 16r^2-8r+1=0

The zeros of 16r^2-8r+1=0 are r= 1/4

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16 r^{2} - 8 r + 1 = 0

r = \frac{1}{4}

Decimal Notation

r = 0.25

Solution steps

16 r^{2} - 8 r + 1 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 16 \cdot 1}{2 \cdot 16}

(- 8)^{2} - 4 \cdot 16 \cdot 1 = 0

r_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 16}

r = \frac{- ( - 8 )}{2 \cdot 16}

\frac{- ( - 8 )}{2 \cdot 16} = \frac{1}{4}

r = \frac{1}{4}

The solution to the quadratic equation is:

r = \frac{1}{4}

57 x + 57 = - 75 x - 75

X - 11 \leq 0

0 = - (x + 1)^{2}

\frac{3}{5} ab + \frac{1}{10} ab

(x - 1)^{2} = (2 x + 6)

What are the solutions to the equation 16r^2-8r+1=0 ?
The solutions to the equation 16r^2-8r+1=0 are r= 1/4
Find the zeros of 16r^2-8r+1=0
The zeros of 16r^2-8r+1=0 are r= 1/4