What are the solutions to the equation 5x^2-10x=1 ?

The solutions to the equation 5x^2-10x=1 are x=(5+sqrt(30))/5 ,x=(5-sqrt(30))/5

Find the zeros of 5x^2-10x=1

The zeros of 5x^2-10x=1 are x=(5+sqrt(30))/5 ,x=(5-sqrt(30))/5

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5 x^{2} - 10 x = 1

x = \frac{5 + 30}{5}, x = \frac{5 - 30}{5}

Decimal Notation

x = 2.09544 \dots, x = - 0.09544 \dots

Solution steps

5 x^{2} - 10 x = 1

Move

1

to the left side

5 x^{2} - 10 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 5 ( - 1 )}{2 \cdot 5}

(- 10)^{2} - 4 \cdot 5 (- 1) = 230

x_{1, 2} = \frac{- ( - 10 ) \pm 2 30}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 30}{2 \cdot 5}, x_{2} = \frac{- ( - 10 ) - 2 30}{2 \cdot 5}

x = \frac{- ( - 10 ) + 2 30}{2 \cdot 5} : \frac{5 + 30}{5}

x = \frac{- ( - 10 ) - 2 30}{2 \cdot 5} : \frac{5 - 30}{5}

The solutions to the quadratic equation are:

x = \frac{5 + 30}{5}, x = \frac{5 - 30}{5}

r^{6} + s^{6}

(4 x^{2} y^{5})^{- 2}

5 x^{2} + 2 x + 1 = 0

\frac{1}{3} (1)^{2}

x^{2} + 20 x = 0

What are the solutions to the equation 5x^2-10x=1 ?
The solutions to the equation 5x^2-10x=1 are x=(5+sqrt(30))/5 ,x=(5-sqrt(30))/5
Find the zeros of 5x^2-10x=1
The zeros of 5x^2-10x=1 are x=(5+sqrt(30))/5 ,x=(5-sqrt(30))/5