What are the solutions to the equation 5x^2+2x+1=0 ?

The solutions to the equation 5x^2+2x+1=0 are x=-1/5+i 2/5 ,x=-1/5-i 2/5

Find the zeros of 5x^2+2x+1=0

The zeros of 5x^2+2x+1=0 are x=-1/5+i 2/5 ,x=-1/5-i 2/5

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5 x^{2} + 2 x + 1 = 0

x = - \frac{1}{5} + i \frac{2}{5}, x = - \frac{1}{5} - i \frac{2}{5}

Solution steps

5 x^{2} + 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 5 \cdot 1}{2 \cdot 5}

Simplify

2^{2} - 4 \cdot 5 \cdot 1 : 4 i

x_{1, 2} = \frac{- 2 \pm 4 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 2 + 4 i}{2 \cdot 5}, x_{2} = \frac{- 2 - 4 i}{2 \cdot 5}

x = \frac{- 2 + 4 i}{2 \cdot 5} : - \frac{1}{5} + i \frac{2}{5}

x = \frac{- 2 - 4 i}{2 \cdot 5} : - \frac{1}{5} - i \frac{2}{5}

The solutions to the quadratic equation are:

x = - \frac{1}{5} + i \frac{2}{5}, x = - \frac{1}{5} - i \frac{2}{5}

\frac{1}{3} (1)^{2}

x^{2} + 20 x = 0

88 = \frac{[ ( 1.96 + x ) 10 ] ^{2}}{( 25 - 12 ) ^{2}}

x + 6 < 10

3 x^{3} - 3 x

What are the solutions to the equation 5x^2+2x+1=0 ?
The solutions to the equation 5x^2+2x+1=0 are x=-1/5+i 2/5 ,x=-1/5-i 2/5
Find the zeros of 5x^2+2x+1=0
The zeros of 5x^2+2x+1=0 are x=-1/5+i 2/5 ,x=-1/5-i 2/5