What are the solutions to the equation 88=([(1.96+x)10]^2)/((25-12)^2) ?

The solutions to the equation 88=([(1.96+x)10]^2)/((25-12)^2) are x=10.23508…,x=-14.15508…

Find the zeros of 88=([(1.96+x)10]^2)/((25-12)^2)

The zeros of 88=([(1.96+x)10]^2)/((25-12)^2) are x=10.23508…,x=-14.15508…

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88 = \frac{[ ( 1.96 + x ) 10 ] ^{2}}{( 25 - 12 ) ^{2}}

x = 10.23508 \dots, x = - 14.15508 \dots

Solution steps

88 = \frac{[ ( 1.96 + x ) \cdot 10 ] ^{2}}{( 25 - 12 ) ^{2}}

Switch sides

\frac{[ ( 1.96 + x ) \cdot 10 ] ^{2}}{( 25 - 12 ) ^{2}} = 88

Multiply both sides by

(25 - 12)^{2}

[(1.96 + x) 10]^{2} = 14872

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

(1.96 + x) \cdot 10 = 14872 : x = 10.23508 \dots

Solve

(1.96 + x) \cdot 10 = - 14872 : x = - 14.15508 \dots

The solutions to the quadratic equation are:

x = 10.23508 \dots, x = - 14.15508 \dots

x + 6 < 10

3 x^{3} - 3 x

3 ∣ x + 1 ∣ \geq - 6

(x + 1) (x - 2) + 3 y (x - 2)

(x + 3)^{2} = 4

What are the solutions to the equation 88=([(1.96+x)10]^2)/((25-12)^2) ?
The solutions to the equation 88=([(1.96+x)10]^2)/((25-12)^2) are x=10.23508…,x=-14.15508…
Find the zeros of 88=([(1.96+x)10]^2)/((25-12)^2)
The zeros of 88=([(1.96+x)10]^2)/((25-12)^2) are x=10.23508…,x=-14.15508…