What are the solutions to the equation (x+3)^2=4 ?

The solutions to the equation (x+3)^2=4 are x=-1,x=-5

Find the zeros of (x+3)^2=4

The zeros of (x+3)^2=4 are x=-1,x=-5

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(x + 3)^{2} = 4

x = - 1, x = - 5

Solution steps

(x + 3)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 4 : x = - 1

Solve

x + 3 = - 4 : x = - 5

The solutions to the quadratic equation are:

x = - 1, x = - 5

x^{2} + (- \frac{3}{5})^{2} = 1

i z = 4 - z i

20 v^{2} + 3 v - 5 v^{2} - 5 v - 1

\frac{x}{- 6} \geq - 20

\frac{1}{2} x + \frac{1}{8} x = - 1

What are the solutions to the equation (x+3)^2=4 ?
The solutions to the equation (x+3)^2=4 are x=-1,x=-5
Find the zeros of (x+3)^2=4
The zeros of (x+3)^2=4 are x=-1,x=-5