What is factor 2a+ab+2c+bc ?

The solution to factor 2a+ab+2c+bc is (a+c)(2+b)

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factor 2a+ab+2c+bc

factor

2 a + ab + 2 c + b c

(a + c) (2 + b)

Solution steps

2 a + ab + 2 c + b c

Factor out common term

2

= 2 (a + c) + ab + b c

Factor out common term

b

= 2 (a + c) + b (a + c)

Factor out common term

(a + c)

= (a + c) (2 + b)

x^{2} - 12 x > 0

- 3 x + 2 = - 7

\frac{2 - i}{3 - i} - \frac{1}{5} (\frac{1 + 8 i}{1 + 3 i})

(\frac{9 + 5 i}{3 - 2 i})^{2}

72 + 32 + 18