What are the solutions to the equation 6x^2+17x-14=0 ?

The solutions to the equation 6x^2+17x-14=0 are x= 2/3 ,x=-7/2

Find the zeros of 6x^2+17x-14=0

The zeros of 6x^2+17x-14=0 are x= 2/3 ,x=-7/2

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6 x^{2} + 17 x - 14 = 0

x = \frac{2}{3}, x = - \frac{7}{2}

Solution steps

6 x^{2} + 17 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 6 ( - 14 )}{2 \cdot 6}

1 7^{2} - 4 \cdot 6 (- 14) = 25

x_{1, 2} = \frac{- 17 \pm 25}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 17 + 25}{2 \cdot 6}, x_{2} = \frac{- 17 - 25}{2 \cdot 6}

x = \frac{- 17 + 25}{2 \cdot 6} : \frac{2}{3}

x = \frac{- 17 - 25}{2 \cdot 6} : - \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - \frac{7}{2}

5 x^{2} - 2 x + 1 = 0

(1 + \frac{0.04}{2})^{\frac{1}{6}} - 1

\frac{1}{2} (x - 4) > x + 1

- 6 a > - 42

2 x^{2} - 36 = x

What are the solutions to the equation 6x^2+17x-14=0 ?
The solutions to the equation 6x^2+17x-14=0 are x= 2/3 ,x=-7/2
Find the zeros of 6x^2+17x-14=0
The zeros of 6x^2+17x-14=0 are x= 2/3 ,x=-7/2