What are the solutions to the equation 5x^2-2x+1=0 ?

The solutions to the equation 5x^2-2x+1=0 are x= 1/5+i 2/5 ,x= 1/5-i 2/5

Find the zeros of 5x^2-2x+1=0

The zeros of 5x^2-2x+1=0 are x= 1/5+i 2/5 ,x= 1/5-i 2/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} - 2 x + 1 = 0

x = \frac{1}{5} + i \frac{2}{5}, x = \frac{1}{5} - i \frac{2}{5}

Solution steps

5 x^{2} - 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 5 \cdot 1}{2 \cdot 5}

Simplify

(- 2)^{2} - 4 \cdot 5 \cdot 1 : 4 i

x_{1, 2} = \frac{- ( - 2 ) \pm 4 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4 i}{2 \cdot 5}, x_{2} = \frac{- ( - 2 ) - 4 i}{2 \cdot 5}

x = \frac{- ( - 2 ) + 4 i}{2 \cdot 5} : \frac{1}{5} + i \frac{2}{5}

x = \frac{- ( - 2 ) - 4 i}{2 \cdot 5} : \frac{1}{5} - i \frac{2}{5}

The solutions to the quadratic equation are:

x = \frac{1}{5} + i \frac{2}{5}, x = \frac{1}{5} - i \frac{2}{5}

(1 + \frac{0.04}{2})^{\frac{1}{6}} - 1

\frac{1}{2} (x - 4) > x + 1

- 6 a > - 42

2 x^{2} - 36 = x

9 x^{2} + 9 x + 52 = 0

What are the solutions to the equation 5x^2-2x+1=0 ?
The solutions to the equation 5x^2-2x+1=0 are x= 1/5+i 2/5 ,x= 1/5-i 2/5
Find the zeros of 5x^2-2x+1=0
The zeros of 5x^2-2x+1=0 are x= 1/5+i 2/5 ,x= 1/5-i 2/5