What are the solutions to the equation 4x^2+x-3=0 ?

The solutions to the equation 4x^2+x-3=0 are x= 3/4 ,x=-1

Find the zeros of 4x^2+x-3=0

The zeros of 4x^2+x-3=0 are x= 3/4 ,x=-1

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4 x^{2} + x - 3 = 0

x = \frac{3}{4}, x = - 1

Decimal Notation

x = 0.75, x = - 1

Solution steps

4 x^{2} + x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

1^{2} - 4 \cdot 4 (- 3) = 7

x_{1, 2} = \frac{- 1 \pm 7}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 1 + 7}{2 \cdot 4}, x_{2} = \frac{- 1 - 7}{2 \cdot 4}

x = \frac{- 1 + 7}{2 \cdot 4} : \frac{3}{4}

x = \frac{- 1 - 7}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

x = \frac{3}{4}, x = - 1

x y - 7 x + 3 y - 21

16 y^{2} + 0 y + 10 = 0

x (x - 1) - 2 x = - 6 x

5 x^{2} + 12 x + 7

(500 \cdot 10 \cdot 70) = (500 \cdot 10 \cdot 30) + (\frac{1}{2} \cdot 500 \cdot x^{2})

What are the solutions to the equation 4x^2+x-3=0 ?
The solutions to the equation 4x^2+x-3=0 are x= 3/4 ,x=-1
Find the zeros of 4x^2+x-3=0
The zeros of 4x^2+x-3=0 are x= 3/4 ,x=-1