What are the solutions to the equation 3x^2+x-6=0 ?

The solutions to the equation 3x^2+x-6=0 are x=(-1+sqrt(73))/6 ,x=(-1-sqrt(73))/6

Find the zeros of 3x^2+x-6=0

The zeros of 3x^2+x-6=0 are x=(-1+sqrt(73))/6 ,x=(-1-sqrt(73))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + x - 6 = 0

x = \frac{- 1 + 73}{6}, x = \frac{- 1 - 73}{6}

Solution steps

3 x^{2} + x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 6) = 73

x_{1, 2} = \frac{- 1 \pm 73}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 1 + 73}{2 \cdot 3}, x_{2} = \frac{- 1 - 73}{2 \cdot 3}

x = \frac{- 1 + 73}{2 \cdot 3} : \frac{- 1 + 73}{6}

x = \frac{- 1 - 73}{2 \cdot 3} : \frac{- 1 - 73}{6}

The solutions to the quadratic equation are:

x = \frac{- 1 + 73}{6}, x = \frac{- 1 - 73}{6}

2 x^{2} - 13 x + 14 = 0

192 x^{2} - 243 y^{3}

2 0^{2}

x y^{3} + y

\frac{1}{2} y^{2} - \frac{5}{2} y - 7

What are the solutions to the equation 3x^2+x-6=0 ?
The solutions to the equation 3x^2+x-6=0 are x=(-1+sqrt(73))/6 ,x=(-1-sqrt(73))/6
Find the zeros of 3x^2+x-6=0
The zeros of 3x^2+x-6=0 are x=(-1+sqrt(73))/6 ,x=(-1-sqrt(73))/6