What are the solutions to the equation -0.3t^2+27t=0 ?

The solutions to the equation -0.3t^2+27t=0 are t=0,t=90

Find the zeros of -0.3t^2+27t=0

The zeros of -0.3t^2+27t=0 are t=0,t=90

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- 0.3 t^{2} + 27 t = 0

t = 0, t = 90

Solution steps

- 0.3 t^{2} + 27 t = 0

Multiply both sides by

10

- 3 t^{2} + 270 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 270 \pm 27 0 ^{2} - 4 ( - 3 ) \cdot 0}{2 ( - 3 )}

27 0^{2} - 4 (- 3) \cdot 0 = 270

t_{1, 2} = \frac{- 270 \pm 270}{2 ( - 3 )}

Separate the solutions

t_{1} = \frac{- 270 + 270}{2 ( - 3 )}, t_{2} = \frac{- 270 - 270}{2 ( - 3 )}

t = \frac{- 270 + 270}{2 ( - 3 )} : 0

t = \frac{- 270 - 270}{2 ( - 3 )} : 90

The solutions to the quadratic equation are:

t = 0, t = 90

\frac{4}{5} \cdot \frac{10}{9}

25 x^{2} - 13 x = 10 x^{2} - 7

62 \cdot 2

1 = \frac{3}{2} (3 x - 4)

y^{2} + 6 y - 55 = 0

What are the solutions to the equation -0.3t^2+27t=0 ?
The solutions to the equation -0.3t^2+27t=0 are t=0,t=90
Find the zeros of -0.3t^2+27t=0
The zeros of -0.3t^2+27t=0 are t=0,t=90