What are the solutions to the equation y^2+6y-55=0 ?

The solutions to the equation y^2+6y-55=0 are y=5,y=-11

Find the zeros of y^2+6y-55=0

The zeros of y^2+6y-55=0 are y=5,y=-11

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y^{2} + 6 y - 55 = 0

y = 5, y = - 11

Solution steps

y^{2} + 6 y - 55 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 55 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 55) = 16

y_{1, 2} = \frac{- 6 \pm 16}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 6 + 16}{2 \cdot 1}, y_{2} = \frac{- 6 - 16}{2 \cdot 1}

y = \frac{- 6 + 16}{2 \cdot 1} : 5

y = \frac{- 6 - 16}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

y = 5, y = - 11

w^{2} = 4

i^{2} = 1

(2 x + y)^{2} - 9 (2 x + y) + 20

\frac{π}{2} \cdot π

\frac{1}{2} \cdot \frac{5}{2}

What are the solutions to the equation y^2+6y-55=0 ?
The solutions to the equation y^2+6y-55=0 are y=5,y=-11
Find the zeros of y^2+6y-55=0
The zeros of y^2+6y-55=0 are y=5,y=-11