What are the solutions to the equation -0.6t^2+36t=0 ?

The solutions to the equation -0.6t^2+36t=0 are t=0,t=60

Find the zeros of -0.6t^2+36t=0

The zeros of -0.6t^2+36t=0 are t=0,t=60

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- 0.6 t^{2} + 36 t = 0

t = 0, t = 60

Solution steps

- 0.6 t^{2} + 36 t = 0

Multiply both sides by

10

- 6 t^{2} + 360 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 360 \pm 36 0 ^{2} - 4 ( - 6 ) \cdot 0}{2 ( - 6 )}

36 0^{2} - 4 (- 6) \cdot 0 = 360

t_{1, 2} = \frac{- 360 \pm 360}{2 ( - 6 )}

Separate the solutions

t_{1} = \frac{- 360 + 360}{2 ( - 6 )}, t_{2} = \frac{- 360 - 360}{2 ( - 6 )}

t = \frac{- 360 + 360}{2 ( - 6 )} : 0

t = \frac{- 360 - 360}{2 ( - 6 )} : 60

The solutions to the quadratic equation are:

t = 0, t = 60

7 (2 y - 10) = 14

4 t - 2 < - 22 or 3 t + 4 \geq 10

3 x^{2} + 25 x - 8.3 = 0

4 c^{2} + 15 c + 4 = 0

∣ 2 x - 3 ∣ \geq 2

What are the solutions to the equation -0.6t^2+36t=0 ?
The solutions to the equation -0.6t^2+36t=0 are t=0,t=60
Find the zeros of -0.6t^2+36t=0
The zeros of -0.6t^2+36t=0 are t=0,t=60