What are the solutions to the equation (x+4)(x-12)=0 ?

The solutions to the equation (x+4)(x-12)=0 are x=-4,x=12

Find the zeros of (x+4)(x-12)=0

The zeros of (x+4)(x-12)=0 are x=-4,x=12

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(x + 4) (x - 12) = 0

x = - 4, x = 12

Solution steps

(x + 4) (x - 12) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or x - 12 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x - 12 = 0 : x = 12

The solutions to the quadratic equation are:

x = - 4, x = 12

6 x - 11 = 2 x + 9

(x - 1) (x + 5) = - 8

\frac{π}{8} + π

(- 9) (- 4)

21 - 3 h = 6 - 6 h

What are the solutions to the equation (x+4)(x-12)=0 ?
The solutions to the equation (x+4)(x-12)=0 are x=-4,x=12
Find the zeros of (x+4)(x-12)=0
The zeros of (x+4)(x-12)=0 are x=-4,x=12