What are the solutions to the equation (x-1)(x+5)=-8 ?

The solutions to the equation (x-1)(x+5)=-8 are x=-1,x=-3

Find the zeros of (x-1)(x+5)=-8

The zeros of (x-1)(x+5)=-8 are x=-1,x=-3

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(x - 1) (x + 5) = - 8

x = - 1, x = - 3

Solution steps

(x - 1) (x + 5) = - 8

Expand

(x - 1) (x + 5) : x^{2} + 4 x - 5

x^{2} + 4 x - 5 = - 8

Move

8

to the left side

x^{2} + 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 3 = 2

x_{1, 2} = \frac{- 4 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2}{2 \cdot 1}, x_{2} = \frac{- 4 - 2}{2 \cdot 1}

x = \frac{- 4 + 2}{2 \cdot 1} : - 1

x = \frac{- 4 - 2}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = - 1, x = - 3

\frac{π}{8} + π

(- 9) (- 4)

21 - 3 h = 6 - 6 h

(4 x + 7)^{2} = 36

(\frac{3 x ^{5} y ^{4}}{x ^{0} y ^{- 3}})^{2}

What are the solutions to the equation (x-1)(x+5)=-8 ?
The solutions to the equation (x-1)(x+5)=-8 are x=-1,x=-3
Find the zeros of (x-1)(x+5)=-8
The zeros of (x-1)(x+5)=-8 are x=-1,x=-3