What are the solutions to the equation a^2+7a+10=0 ?

The solutions to the equation a^2+7a+10=0 are a=-2,a=-5

Find the zeros of a^2+7a+10=0

The zeros of a^2+7a+10=0 are a=-2,a=-5

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a^{2} + 7 a + 10 = 0

a = - 2, a = - 5

Solution steps

a^{2} + 7 a + 10 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 10 = 3

a_{1, 2} = \frac{- 7 \pm 3}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 7 + 3}{2 \cdot 1}, a_{2} = \frac{- 7 - 3}{2 \cdot 1}

a = \frac{- 7 + 3}{2 \cdot 1} : - 2

a = \frac{- 7 - 3}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

a = - 2, a = - 5

3 x^{2} + 6 = 7 x

81 x^{2} + 36 x + 4

3 x^{2} = 10 - x

x^{3} - x^{2} - 25 x + 25 > 0

\frac{8 ( 0.36 )}{20 ( 1 - 7 e ^{- 6} )}

What are the solutions to the equation a^2+7a+10=0 ?
The solutions to the equation a^2+7a+10=0 are a=-2,a=-5
Find the zeros of a^2+7a+10=0
The zeros of a^2+7a+10=0 are a=-2,a=-5