What are the solutions to the equation 3x^2+6=7x ?

The solutions to the equation 3x^2+6=7x are x= 7/6+i(sqrt(23))/6 ,x= 7/6-i(sqrt(23))/6

Find the zeros of 3x^2+6=7x

The zeros of 3x^2+6=7x are x= 7/6+i(sqrt(23))/6 ,x= 7/6-i(sqrt(23))/6

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3 x^{2} + 6 = 7 x

x = \frac{7}{6} + i \frac{23}{6}, x = \frac{7}{6} - i \frac{23}{6}

Solution steps

3 x^{2} + 6 = 7 x

Move

7 x

to the left side

3 x^{2} + 6 - 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 7 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 \cdot 6}{2 \cdot 3}

Simplify

(- 7)^{2} - 4 \cdot 3 \cdot 6 : 23 i

x_{1, 2} = \frac{- ( - 7 ) \pm 23 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 23 i}{2 \cdot 3}, x_{2} = \frac{- ( - 7 ) - 23 i}{2 \cdot 3}

x = \frac{- ( - 7 ) + 23 i}{2 \cdot 3} : \frac{7}{6} + i \frac{23}{6}

x = \frac{- ( - 7 ) - 23 i}{2 \cdot 3} : \frac{7}{6} - i \frac{23}{6}

The solutions to the quadratic equation are:

x = \frac{7}{6} + i \frac{23}{6}, x = \frac{7}{6} - i \frac{23}{6}

81 x^{2} + 36 x + 4

3 x^{2} = 10 - x

x^{3} - x^{2} - 25 x + 25 > 0

\frac{8 ( 0.36 )}{20 ( 1 - 7 e ^{- 6} )}

16 x^{2} + 48 x + 37 = 0

What are the solutions to the equation 3x^2+6=7x ?
The solutions to the equation 3x^2+6=7x are x= 7/6+i(sqrt(23))/6 ,x= 7/6-i(sqrt(23))/6
Find the zeros of 3x^2+6=7x
The zeros of 3x^2+6=7x are x= 7/6+i(sqrt(23))/6 ,x= 7/6-i(sqrt(23))/6