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Popular >

2x^2+x-1>= 0

Solution

2 x^{2} + x - 1 \geq 0

Solution

x \leq - 1 or x \geq \frac{1}{2}

+2

Interval Notation

(- \infty, - 1] \cup [\frac{1}{2}, \infty)

Decimal Notation

x \leq - 1 or x \geq 0.5

Solution steps

2 x^{2} + x - 1 \geq 0

Factor

2 x^{2} + x - 1 : (2 x - 1) (x + 1)

(2 x - 1) (x + 1) \geq 0

Identify the intervals

x \leq - 1 or x \geq \frac{1}{2}

Popular Examples

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3 z - 2 \geq - 1 (- 5 z - 2) + 4

(x+3)(x-3)=5(x+2)+31

(x + 3) (x - 3) = 5 (x + 2) + 31

simplify (x^2-y^2)/(3x)*(3y)/(x+y)simplify

\frac{x ^{2} - y ^{2}}{3 x} \cdot \frac{3 y}{x + y}

x^{2} < 3 - 2 x

((2x+1))/6-((x-3))/3 =((4x-1))/3+((x-6))/2

\frac{( 2 x + 1 )}{6} - \frac{( x - 3 )}{3} = \frac{( 4 x - 1 )}{3} + \frac{( x - 6 )}{2}

Frequently Asked Questions (FAQ)

What is 2x^2+x-1>= 0 ?
The solution to 2x^2+x-1>= 0 is x<=-1\lor x>= 1/2