What are the solutions to the equation x^2+12=8x ?

The solutions to the equation x^2+12=8x are x=6,x=2

Find the zeros of x^2+12=8x

The zeros of x^2+12=8x are x=6,x=2

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x^{2} + 12 = 8 x

x = 6, x = 2

Solution steps

x^{2} + 12 = 8 x

Move

8 x

to the left side

x^{2} + 12 - 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 8 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 12 = 4

x_{1, 2} = \frac{- ( - 8 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 4}{2 \cdot 1}

x = \frac{- ( - 8 ) + 4}{2 \cdot 1} : 6

x = \frac{- ( - 8 ) - 4}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 6, x = 2

(3 z - 18)^{2} + 59 = 14

\frac{3 ( x - 5 )}{4} - x = 1 - \frac{x}{6}

32 < \frac{h}{13} + 33

- \frac{x}{8} = 5

\frac{4}{5} + \frac{2}{10}

What are the solutions to the equation x^2+12=8x ?
The solutions to the equation x^2+12=8x are x=6,x=2
Find the zeros of x^2+12=8x
The zeros of x^2+12=8x are x=6,x=2