What are the solutions to the equation w^2-8w+7=0 ?

The solutions to the equation w^2-8w+7=0 are w=7,w=1

Find the zeros of w^2-8w+7=0

The zeros of w^2-8w+7=0 are w=7,w=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

w^{2} - 8 w + 7 = 0

w = 7, w = 1

Solution steps

w^{2} - 8 w + 7 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 7 = 6

w_{1, 2} = \frac{- ( - 8 ) \pm 6}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 8 ) + 6}{2 \cdot 1}, w_{2} = \frac{- ( - 8 ) - 6}{2 \cdot 1}

w = \frac{- ( - 8 ) + 6}{2 \cdot 1} : 7

w = \frac{- ( - 8 ) - 6}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

w = 7, w = 1

3 h^{2} = h^{2} + 18

a^{3} - m^{3} n^{9}

\frac{3}{5} + \frac{7}{4}

4 x^{2} - 4 x + 1 = 9

x^{2} - 9 y^{2}

What are the solutions to the equation w^2-8w+7=0 ?
The solutions to the equation w^2-8w+7=0 are w=7,w=1
Find the zeros of w^2-8w+7=0
The zeros of w^2-8w+7=0 are w=7,w=1