What are the solutions to the equation x^2+4x=60 ?

The solutions to the equation x^2+4x=60 are x=6,x=-10

Find the zeros of x^2+4x=60

The zeros of x^2+4x=60 are x=6,x=-10

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x^{2} + 4 x = 60

x = 6, x = - 10

Solution steps

x^{2} + 4 x = 60

Move

60

to the left side

x^{2} + 4 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 60 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 60) = 16

x_{1, 2} = \frac{- 4 \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 16}{2 \cdot 1}, x_{2} = \frac{- 4 - 16}{2 \cdot 1}

x = \frac{- 4 + 16}{2 \cdot 1} : 6

x = \frac{- 4 - 16}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 6, x = - 10

x^{2} - 10 x - 49 = 7

6 x^{2} + 150 = 0

x^{4} - 2 x^{2} - 63

- 0.13633 (x)^{2} - 3.00066 (x) + 73.59566 = 24.91

10 x - 4 (x + 1) \geq 13 + 3 x

What are the solutions to the equation x^2+4x=60 ?
The solutions to the equation x^2+4x=60 are x=6,x=-10
Find the zeros of x^2+4x=60
The zeros of x^2+4x=60 are x=6,x=-10