What are the solutions to the equation (x-4)^2-72=0 ?

The solutions to the equation (x-4)^2-72=0 are x=6sqrt(2)+4,x=-6sqrt(2)+4

Find the zeros of (x-4)^2-72=0

The zeros of (x-4)^2-72=0 are x=6sqrt(2)+4,x=-6sqrt(2)+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x - 4)^{2} - 72 = 0

x = 62 + 4, x = - 62 + 4

Decimal Notation

x = 12.48528 \dots, x = - 4.48528 \dots

Solution steps

(x - 4)^{2} - 72 = 0

Move

72

to the right side

(x - 4)^{2} = 72

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 72 : x = 62 + 4

Solve

x - 4 = - 72 : x = - 62 + 4

The solutions to the quadratic equation are:

x = 62 + 4, x = - 62 + 4

\frac{41}{5 + 4 i}

\frac{a - b}{a ^{2} + ab} + \frac{a + b}{ab} - \frac{a}{ab + b ^{2}}

y, x^{2} + y^{2} - 6 x - 10 y + 34 = 0

- 9 p^{2} - 3 = 0

\frac{x ^{2}}{x + 1} \geq - 1

What are the solutions to the equation (x-4)^2-72=0 ?
The solutions to the equation (x-4)^2-72=0 are x=6sqrt(2)+4,x=-6sqrt(2)+4
Find the zeros of (x-4)^2-72=0
The zeros of (x-4)^2-72=0 are x=6sqrt(2)+4,x=-6sqrt(2)+4