What are the solutions to the equation -9p^2-3=0 ?

The solutions to the equation -9p^2-3=0 are p= 1/(sqrt(3))i,p=-1/(sqrt(3))i

Find the zeros of -9p^2-3=0

The zeros of -9p^2-3=0 are p= 1/(sqrt(3))i,p=-1/(sqrt(3))i

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- 9 p^{2} - 3 = 0

p = \frac{1}{3} i, p = - \frac{1}{3} i

Solution steps

- 9 p^{2} - 3 = 0

Move

3

to the right side

- 9 p^{2} = 3

Divide both sides by

- 9

p^{2} = - \frac{1}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = - \frac{1}{3}, p = - - \frac{1}{3}

- \frac{1}{3} = \frac{1}{3} i

- - \frac{1}{3} = - \frac{1}{3} i

p = \frac{1}{3} i, p = - \frac{1}{3} i

\frac{x ^{2}}{x + 1} \geq - 1

(x + 2) (x - 2) = 0

3 \times 1 0^{8}

4^{6}

11 - 3 x = 44

What are the solutions to the equation -9p^2-3=0 ?
The solutions to the equation -9p^2-3=0 are p= 1/(sqrt(3))i,p=-1/(sqrt(3))i
Find the zeros of -9p^2-3=0
The zeros of -9p^2-3=0 are p= 1/(sqrt(3))i,p=-1/(sqrt(3))i