What are the solutions to the equation (x+2)(x-2)=0 ?

The solutions to the equation (x+2)(x-2)=0 are x=-2,x=2

Find the zeros of (x+2)(x-2)=0

The zeros of (x+2)(x-2)=0 are x=-2,x=2

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(x + 2) (x - 2) = 0

x = - 2, x = 2

Solution steps

(x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x - 2 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions to the quadratic equation are:

x = - 2, x = 2

3 \times 1 0^{8}

4^{6}

11 - 3 x = 44

x^{3} - 3 x^{2} + 2

\frac{x + 2}{3} \cdot \frac{x - 2}{3} = 5

What are the solutions to the equation (x+2)(x-2)=0 ?
The solutions to the equation (x+2)(x-2)=0 are x=-2,x=2
Find the zeros of (x+2)(x-2)=0
The zeros of (x+2)(x-2)=0 are x=-2,x=2