What are the solutions to the equation (x+2)/3*(x-2)/3 =5 ?

The solutions to the equation (x+2)/3*(x-2)/3 =5 are x=7,x=-7

Find the zeros of (x+2)/3*(x-2)/3 =5

The zeros of (x+2)/3*(x-2)/3 =5 are x=7,x=-7

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\frac{x + 2}{3} \cdot \frac{x - 2}{3} = 5

x = 7, x = - 7

Solution steps

\frac{x + 2}{3} \cdot \frac{x - 2}{3} = 5

Simplify

3 \cdot 3 : 9

\frac{( x + 2 ) ( x - 2 )}{9} = 5

Multiply both sides by

9

(x + 2) (x - 2) = 45

Expand

(x + 2) (x - 2) : x^{2} - 4

x^{2} - 4 = 45

Move

45

to the left side

x^{2} - 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot ( - 49 )}{2 \cdot 1}

0^{2} - 4 \cdot 1 \cdot (- 49) = 14

x_{1, 2} = \frac{- 0 \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 0 + 14}{2 \cdot 1}, x_{2} = \frac{- 0 - 14}{2 \cdot 1}

x = \frac{- 0 + 14}{2 \cdot 1} : 7

x = \frac{- 0 - 14}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 7, x = - 7

1.25 + \frac{41.183}{- 32}

- 9 x^{2} + 18 x = 16

(3 x + 2) (x + 1) = 1

y + x^{3} y^{4}

15 x^{2} - 34 x + 15

What are the solutions to the equation (x+2)/3*(x-2)/3 =5 ?
The solutions to the equation (x+2)/3*(x-2)/3 =5 are x=7,x=-7
Find the zeros of (x+2)/3*(x-2)/3 =5
The zeros of (x+2)/3*(x-2)/3 =5 are x=7,x=-7