What are the solutions to the equation 8x^2+3x=7 ?

The solutions to the equation 8x^2+3x=7 are x=(-3+sqrt(233))/(16),x=(-3-sqrt(233))/(16)

Find the zeros of 8x^2+3x=7

The zeros of 8x^2+3x=7 are x=(-3+sqrt(233))/(16),x=(-3-sqrt(233))/(16)

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8 x^{2} + 3 x = 7

x = \frac{- 3 + 233}{16}, x = \frac{- 3 - 233}{16}

Decimal Notation

x = 0.76652 \dots, x = - 1.14152 \dots

Solution steps

8 x^{2} + 3 x = 7

Move

7

to the left side

8 x^{2} + 3 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 8 ( - 7 )}{2 \cdot 8}

3^{2} - 4 \cdot 8 (- 7) = 233

x_{1, 2} = \frac{- 3 \pm 233}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 3 + 233}{2 \cdot 8}, x_{2} = \frac{- 3 - 233}{2 \cdot 8}

x = \frac{- 3 + 233}{2 \cdot 8} : \frac{- 3 + 233}{16}

x = \frac{- 3 - 233}{2 \cdot 8} : \frac{- 3 - 233}{16}

The solutions to the quadratic equation are:

x = \frac{- 3 + 233}{16}, x = \frac{- 3 - 233}{16}

\frac{7}{3} - \frac{x}{3} = \frac{x}{4}

3 y^{2} - 2 y - 8 = 0

\frac{1}{9} + 1

10 = 31.9131246 x + 10.7438939

i^{6}

What are the solutions to the equation 8x^2+3x=7 ?
The solutions to the equation 8x^2+3x=7 are x=(-3+sqrt(233))/(16),x=(-3-sqrt(233))/(16)
Find the zeros of 8x^2+3x=7
The zeros of 8x^2+3x=7 are x=(-3+sqrt(233))/(16),x=(-3-sqrt(233))/(16)