What are the solutions to the equation a^2+24^2=25^2 ?

The solutions to the equation a^2+24^2=25^2 are a=7,a=-7

Find the zeros of a^2+24^2=25^2

The zeros of a^2+24^2=25^2 are a=7,a=-7

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a^{2} + 2 4^{2} = 2 5^{2}

a = 7, a = - 7

Solution steps

a^{2} + 2 4^{2} = 2 5^{2}

Move

2 4^{2}

to the right side

a^{2} = 49

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 49, a = - 49

49 = 7

- 49 = - 7

a = 7, a = - 7

∣ x - 7 ∣ \leq 14

6 (\frac{1}{3})^{- 2}

\frac{7 k - 3}{4} = \frac{13 - 5 k}{8}

- 17 - \frac{1}{3} x \geq 4

What are the solutions to the equation a^2+24^2=25^2 ?
The solutions to the equation a^2+24^2=25^2 are a=7,a=-7
Find the zeros of a^2+24^2=25^2
The zeros of a^2+24^2=25^2 are a=7,a=-7