What are the solutions to the equation 6x^2+11x=2 ?

The solutions to the equation 6x^2+11x=2 are x= 1/6 ,x=-2

Find the zeros of 6x^2+11x=2

The zeros of 6x^2+11x=2 are x= 1/6 ,x=-2

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6 x^{2} + 11 x = 2

x = \frac{1}{6}, x = - 2

Decimal Notation

x = 0.16666 \dots, x = - 2

Solution steps

6 x^{2} + 11 x = 2

Move

2

to the left side

6 x^{2} + 11 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 6 ( - 2 )}{2 \cdot 6}

1 1^{2} - 4 \cdot 6 (- 2) = 13

x_{1, 2} = \frac{- 11 \pm 13}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 11 + 13}{2 \cdot 6}, x_{2} = \frac{- 11 - 13}{2 \cdot 6}

x = \frac{- 11 + 13}{2 \cdot 6} : \frac{1}{6}

x = \frac{- 11 - 13}{2 \cdot 6} : - 2

The solutions to the quadratic equation are:

x = \frac{1}{6}, x = - 2

- 4 + 3 x - 1 = 2 x + 1 + 2 x

6 x^{4} + 24 x^{3} + 24 x^{2}

x^{2} + 1 \leq x \leq 9

x + \frac{1}{3} [x - 3 - \frac{1}{2} (4 - 3 x)] = 0

∣ 2 x - 7 ∣ \leq 11

What are the solutions to the equation 6x^2+11x=2 ?
The solutions to the equation 6x^2+11x=2 are x= 1/6 ,x=-2
Find the zeros of 6x^2+11x=2
The zeros of 6x^2+11x=2 are x= 1/6 ,x=-2