What is |1-x^2|>x-1 ?

The solution to |1-x^2|>x-1 is x 1

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|1-x^2|>x-1

1 - x^{2} > x - 1

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

1 - x^{2} > x - 1

Find positive and negative intervals

x < - 1, - 1 \leq x \leq 1, x > 1

Solve the inequality for each interval

x < - 1 or - 1 \leq x < 1 or x > 1

Merge Overlapping Intervals

x < 1 or x > 1

∣ 5 + 2 x ∣ > 0

- z - 1 = - 3 z^{2}

x^{2} - x + 8 = 0

x^{\frac{5}{2}} - 81 x^{\frac{1}{2}}

\frac{2}{3} + \frac{a}{7}