What are the solutions to the equation x^2+6x-8=0 ?

The solutions to the equation x^2+6x-8=0 are x=-3+sqrt(17),x=-3-sqrt(17)

Find the zeros of x^2+6x-8=0

The zeros of x^2+6x-8=0 are x=-3+sqrt(17),x=-3-sqrt(17)

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x^{2} + 6 x - 8 = 0

x = - 3 + 17, x = - 3 - 17

Solution steps

x^{2} + 6 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 8) = 217

x_{1, 2} = \frac{- 6 \pm 2 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 17}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 17}{2 \cdot 1}

x = \frac{- 6 + 2 17}{2 \cdot 1} : - 3 + 17

x = \frac{- 6 - 2 17}{2 \cdot 1} : - 3 - 17

The solutions to the quadratic equation are:

x = - 3 + 17, x = - 3 - 17

1 - 2 ∣ 8 + 4 x ∣ = - 7

4 x^{2} - 16 x + 9 = 0

\frac{4 ( 0.36 )}{20 ( 1 - 7 e ^{- 6} )}

(5 x^{5})^{2}

3 = \frac{g}{4} - 5

What are the solutions to the equation x^2+6x-8=0 ?
The solutions to the equation x^2+6x-8=0 are x=-3+sqrt(17),x=-3-sqrt(17)
Find the zeros of x^2+6x-8=0
The zeros of x^2+6x-8=0 are x=-3+sqrt(17),x=-3-sqrt(17)