What is sqrt(2x+5)+1>4 ?

The solution to sqrt(2x+5)+1>4 is x>2

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sqrt(2x+5)+1>4

2 x + 5 + 1 > 4

x > 2

Interval Notation

(2, \infty)

Solution steps

2 x + 5 + 1 > 4

Move

1

to the right side

2 x + 5 > 3

Square both sides

(2 x + 5)^{2} > 3^{2}

Simplify

2 x + 5 > 9

2 x + 5 > 9 : x > 2

x > 2

Find singularity points

Find non-negative values for radicals:

x \geq - \frac{5}{2}

Combine the intervals

x > 2 and x \geq - \frac{5}{2}

Merge Overlapping Intervals

x > 2

x^{2} + 4 x = 3

a^{3} - 3 + 3 a^{2} - a

y^{2} + 8 y - 2 = 0

13 x^{2} - 38 x - 3

3 0^{\circ} \cdot \frac{π}{18 0 ^{\circ}}