What are the solutions to the equation -8x^2+32x=0 ?

The solutions to the equation -8x^2+32x=0 are x=0,x=4

Find the zeros of -8x^2+32x=0

The zeros of -8x^2+32x=0 are x=0,x=4

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- 8 x^{2} + 32 x = 0

x = 0, x = 4

Solution steps

- 8 x^{2} + 32 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 ( - 8 ) \cdot 0}{2 ( - 8 )}

3 2^{2} - 4 (- 8) \cdot 0 = 32

x_{1, 2} = \frac{- 32 \pm 32}{2 ( - 8 )}

Separate the solutions

x_{1} = \frac{- 32 + 32}{2 ( - 8 )}, x_{2} = \frac{- 32 - 32}{2 ( - 8 )}

x = \frac{- 32 + 32}{2 ( - 8 )} : 0

x = \frac{- 32 - 32}{2 ( - 8 )} : 4

The solutions to the quadratic equation are:

x = 0, x = 4

x^{2} = - 7 + 18

\frac{1.5 \cdot 1 0 ^{- 8}}{6 \cdot 1 0 ^{7}}

(\frac{6 x}{7})^{2}

\frac{- x}{3} + \frac{x}{2} = - 4

6 r^{2} + r - 2 = 0

What are the solutions to the equation -8x^2+32x=0 ?
The solutions to the equation -8x^2+32x=0 are x=0,x=4
Find the zeros of -8x^2+32x=0
The zeros of -8x^2+32x=0 are x=0,x=4