What is factor ((a^2-b^2))/((a^2+2ab+b^2)) ?

The solution to factor ((a^2-b^2))/((a^2+2ab+b^2)) is (a-b)/(a+b)

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factor ((a^2-b^2))/((a^2+2ab+b^2))

factor

\frac{( a ^{2} - b ^{2} )}{( a ^{2} + 2 ab + b ^{2} )}

\frac{a - b}{a + b}

Solution steps

\frac{a ^{2} - b ^{2}}{a ^{2} + 2 ab + b ^{2}}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

a^{2} - b^{2} = (a + b) (a - b)

= \frac{( a + b ) ( a - b )}{a ^{2} + 2 ab + b ^{2}}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = a, b = b

= \frac{( a + b ) ( a - b )}{( a + b ) ^{2}}

Cancel the common factor:

a + b

= \frac{a - b}{a + b}

∣ 3 y + 1 ∣ - 6 = - 2

a^{2} + 3 a = a + 63

(5^{2})^{3}

- 6 x^{3} + 3 x^{2} + 84 x

4 x^{2} = 2.166667

What is factor ((a^2-b^2))/((a^2+2ab+b^2)) ?
The solution to factor ((a^2-b^2))/((a^2+2ab+b^2)) is (a-b)/(a+b)