What is the answer to (x-2)/6-(x+1)/3+(x-1)/2 =0 ?

The answer to (x-2)/6-(x+1)/3+(x-1)/2 =0 is x= 7/2

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(x-2)/6-(x+1)/3+(x-1)/2 =0

\frac{x - 2}{6} - \frac{x + 1}{3} + \frac{x - 1}{2} = 0

x = \frac{7}{2}

Decimal Notation

x = 3.5

Solution steps

\frac{x - 2}{6} - \frac{x + 1}{3} + \frac{x - 1}{2} = 0

Multiply by LCM

x - 2 - 2 (x + 1) + 3 (x - 1) = 0

Expand

x - 2 - 2 (x + 1) + 3 (x - 1) : 2 x - 7

2 x - 7 = 0

Move

7

to the right side

2 x = 7

Divide both sides by

2

x = \frac{7}{2}

6 x^{2} + 7 x + 2

2 x + 1 < 7

1^{2} + x^{2} = 7^{2}

- 3 x + 4 \leq 13

What is the answer to (x-2)/6-(x+1)/3+(x-1)/2 =0 ?
The answer to (x-2)/6-(x+1)/3+(x-1)/2 =0 is x= 7/2
Solve for x: (x-2)/6-(x+1)/3+(x-1)/2 =0
The solution is x= 7/2