What are the solutions to the equation 9p^2=12p-4 ?

The solutions to the equation 9p^2=12p-4 are p= 2/3

Find the zeros of 9p^2=12p-4

The zeros of 9p^2=12p-4 are p= 2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 p^{2} = 12 p - 4

p = \frac{2}{3}

Decimal Notation

p = 0.66666 \dots

Solution steps

9 p^{2} = 12 p - 4

Move

4

to the left side

9 p^{2} + 4 = 12 p

Move

12 p

to the left side

9 p^{2} + 4 - 12 p = 0

Write in the standard form

a x^{2} + b x + c = 0

9 p^{2} - 12 p + 4 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 9 \cdot 4}{2 \cdot 9}

(- 12)^{2} - 4 \cdot 9 \cdot 4 = 0

p_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 9}

p = \frac{- ( - 12 )}{2 \cdot 9}

\frac{- ( - 12 )}{2 \cdot 9} = \frac{2}{3}

p = \frac{2}{3}

The solution to the quadratic equation is:

p = \frac{2}{3}

lo g_{6} (1296)

x^{2} = 33

(c + 8)^{2} = 16

5 x - (x + 3) = 3 (2 - 2 x) + x

d = (3 - 7)^{2} + (2 - 6)^{2}

What are the solutions to the equation 9p^2=12p-4 ?
The solutions to the equation 9p^2=12p-4 are p= 2/3
Find the zeros of 9p^2=12p-4
The zeros of 9p^2=12p-4 are p= 2/3