What are the solutions to the equation x^2+8x=1 ?

The solutions to the equation x^2+8x=1 are x=-4+sqrt(17),x=-4-sqrt(17)

Find the zeros of x^2+8x=1

The zeros of x^2+8x=1 are x=-4+sqrt(17),x=-4-sqrt(17)

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x^{2} + 8 x = 1

x = - 4 + 17, x = - 4 - 17

Solution steps

x^{2} + 8 x = 1

Move

1

to the left side

x^{2} + 8 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 1) = 217

x_{1, 2} = \frac{- 8 \pm 2 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 17}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 17}{2 \cdot 1}

x = \frac{- 8 + 2 17}{2 \cdot 1} : - 4 + 17

x = \frac{- 8 - 2 17}{2 \cdot 1} : - 4 - 17

The solutions to the quadratic equation are:

x = - 4 + 17, x = - 4 - 17

7 x^{2} - 10 x + 9 = 5 - 2 x

\frac{a ^{2} - 4 a c + 3 b c}{a ^{2} - ab + b c - a c} + \frac{a + 3 b}{b - a} + \frac{a + 2 c}{a - c}

6 = \frac{a}{- 4}

1 0^{0}

(\frac{4}{5}) (\frac{15}{17}) + (- \frac{3}{5}) (\frac{8}{17})

What are the solutions to the equation x^2+8x=1 ?
The solutions to the equation x^2+8x=1 are x=-4+sqrt(17),x=-4-sqrt(17)
Find the zeros of x^2+8x=1
The zeros of x^2+8x=1 are x=-4+sqrt(17),x=-4-sqrt(17)