What are the solutions to the equation 5=-x^2+3x ?

The solutions to the equation 5=-x^2+3x are x= 3/2-i(sqrt(11))/2 ,x= 3/2+i(sqrt(11))/2

Find the zeros of 5=-x^2+3x

The zeros of 5=-x^2+3x are x= 3/2-i(sqrt(11))/2 ,x= 3/2+i(sqrt(11))/2

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5 = - x^{2} + 3 x

x = \frac{3}{2} - i \frac{11}{2}, x = \frac{3}{2} + i \frac{11}{2}

Solution steps

5 = - x^{2} + 3 x

Switch sides

- x^{2} + 3 x = 5

Move

5

to the left side

- x^{2} + 3 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) ( - 5 )}{2 ( - 1 )}

Simplify

3^{2} - 4 (- 1) (- 5) : 11 i

x_{1, 2} = \frac{- 3 \pm 11 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 11 i}{2 ( - 1 )}, x_{2} = \frac{- 3 - 11 i}{2 ( - 1 )}

x = \frac{- 3 + 11 i}{2 ( - 1 )} : \frac{3}{2} - i \frac{11}{2}

x = \frac{- 3 - 11 i}{2 ( - 1 )} : \frac{3}{2} + i \frac{11}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} - i \frac{11}{2}, x = \frac{3}{2} + i \frac{11}{2}

\frac{48}{6}

5 + (x - 3) (3 + 2) = 20

x^{2} + 7 x + 6 \leq 0

x^{2} - 9 \leq ∣ x + 3 ∣

2 x - 2 = 2 - 2 x

What are the solutions to the equation 5=-x^2+3x ?
The solutions to the equation 5=-x^2+3x are x= 3/2-i(sqrt(11))/2 ,x= 3/2+i(sqrt(11))/2
Find the zeros of 5=-x^2+3x
The zeros of 5=-x^2+3x are x= 3/2-i(sqrt(11))/2 ,x= 3/2+i(sqrt(11))/2