What are the solutions to the equation 16x^2-3=8x ?

The solutions to the equation 16x^2-3=8x are x= 3/4 ,x=-1/4

Find the zeros of 16x^2-3=8x

The zeros of 16x^2-3=8x are x= 3/4 ,x=-1/4

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16 x^{2} - 3 = 8 x

x = \frac{3}{4}, x = - \frac{1}{4}

Decimal Notation

x = 0.75, x = - 0.25

Solution steps

16 x^{2} - 3 = 8 x

Move

8 x

to the left side

16 x^{2} - 3 - 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

16 x^{2} - 8 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 16 ( - 3 )}{2 \cdot 16}

(- 8)^{2} - 4 \cdot 16 (- 3) = 16

x_{1, 2} = \frac{- ( - 8 ) \pm 16}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 16}{2 \cdot 16}, x_{2} = \frac{- ( - 8 ) - 16}{2 \cdot 16}

x = \frac{- ( - 8 ) + 16}{2 \cdot 16} : \frac{3}{4}

x = \frac{- ( - 8 ) - 16}{2 \cdot 16} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = \frac{3}{4}, x = - \frac{1}{4}

\frac{3}{2 i} + i^{5} - (- 3 i + 2)^{2}

t^{2} + 2 t - 8 = 0

0 = - 25 t^{2} + 200 t + 375

\frac{z}{z - 5} \geq 2 z

27 x - 9

What are the solutions to the equation 16x^2-3=8x ?
The solutions to the equation 16x^2-3=8x are x= 3/4 ,x=-1/4
Find the zeros of 16x^2-3=8x
The zeros of 16x^2-3=8x are x= 3/4 ,x=-1/4