What are the solutions to the equation 8z^2-6z-9=0 ?

The solutions to the equation 8z^2-6z-9=0 are z= 3/2 ,z=-3/4

Find the zeros of 8z^2-6z-9=0

The zeros of 8z^2-6z-9=0 are z= 3/2 ,z=-3/4

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8 z^{2} - 6 z - 9 = 0

z = \frac{3}{2}, z = - \frac{3}{4}

Solution steps

8 z^{2} - 6 z - 9 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 8 ( - 9 )}{2 \cdot 8}

(- 6)^{2} - 4 \cdot 8 (- 9) = 18

z_{1, 2} = \frac{- ( - 6 ) \pm 18}{2 \cdot 8}

Separate the solutions

z_{1} = \frac{- ( - 6 ) + 18}{2 \cdot 8}, z_{2} = \frac{- ( - 6 ) - 18}{2 \cdot 8}

z = \frac{- ( - 6 ) + 18}{2 \cdot 8} : \frac{3}{2}

z = \frac{- ( - 6 ) - 18}{2 \cdot 8} : - \frac{3}{4}

The solutions to the quadratic equation are:

z = \frac{3}{2}, z = - \frac{3}{4}

(\frac{2 ^{- 10}}{4 ^{2}})^{7}

x^{2} - 6 x = 27

7^{2} + 4^{2}

∣ - 3 x - 1 ∣ - 8 > 0

2 (x + 7) \geq 24

What are the solutions to the equation 8z^2-6z-9=0 ?
The solutions to the equation 8z^2-6z-9=0 are z= 3/2 ,z=-3/4
Find the zeros of 8z^2-6z-9=0
The zeros of 8z^2-6z-9=0 are z= 3/2 ,z=-3/4