What are the solutions to the equation r^2-8r+11=0 ?

The solutions to the equation r^2-8r+11=0 are r=4+sqrt(5),r=4-sqrt(5)

Find the zeros of r^2-8r+11=0

The zeros of r^2-8r+11=0 are r=4+sqrt(5),r=4-sqrt(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r^{2} - 8 r + 11 = 0

r = 4 + 5, r = 4 - 5

Decimal Notation

r = 6.23606 \dots, r = 1.76393 \dots

Solution steps

r^{2} - 8 r + 11 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 11}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 11 = 25

r_{1, 2} = \frac{- ( - 8 ) \pm 2 5}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 8 ) + 2 5}{2 \cdot 1}, r_{2} = \frac{- ( - 8 ) - 2 5}{2 \cdot 1}

r = \frac{- ( - 8 ) + 2 5}{2 \cdot 1} : 4 + 5

r = \frac{- ( - 8 ) - 2 5}{2 \cdot 1} : 4 - 5

The solutions to the quadratic equation are:

r = 4 + 5, r = 4 - 5

3 a^{2} + 8 a + 5

(x + 3)^{2} = - 64

y^{2} - 8 y = - 9

c^{3} + b^{6}

(3 + i) (4 + 2 i)

What are the solutions to the equation r^2-8r+11=0 ?
The solutions to the equation r^2-8r+11=0 are r=4+sqrt(5),r=4-sqrt(5)
Find the zeros of r^2-8r+11=0
The zeros of r^2-8r+11=0 are r=4+sqrt(5),r=4-sqrt(5)