What is factor 16v^2-40v+25 ?

The solution to factor 16v^2-40v+25 is (4v-5)^2

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factor 16v^2-40v+25

factor

16 v^{2} - 40 v + 25

(4 v - 5)^{2}

Solution steps

16 v^{2} - 40 v + 25

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

16 v^{2} = (4 v)^{2}

25 = 5^{2}

- 40 v = - 2 \cdot 4 v \cdot 5

= (4 v)^{2} - 2 \cdot 4 v \cdot 5 + 5^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(4 v)^{2} - 2 \cdot 4 v \cdot 5 + 5^{2} = (4 v - 5)^{2}

= (4 v - 5)^{2}

(\frac{2}{5} m^{2}) (am - \frac{2}{7} t m^{3} - m^{4})

- 1.44

- 4 - (- 4)

\frac{2 ( - 0.51 ) + 1}{\frac{1}{4} - ( - 0.5 1 ^{2} )}

2^{k} + 2^{k}