What are the solutions to the equation 16-(x-1)^2=0 ?

The solutions to the equation 16-(x-1)^2=0 are x=5,x=-3

Find the zeros of 16-(x-1)^2=0

The zeros of 16-(x-1)^2=0 are x=5,x=-3

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16 - (x - 1)^{2} = 0

x = 5, x = - 3

Solution steps

16 - (x - 1)^{2} = 0

Move

16

to the right side

- (x - 1)^{2} = - 16

Divide both sides by

- 1

(x - 1)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 16 : x = 5

Solve

x - 1 = - 16 : x = - 3

The solutions to the quadratic equation are:

x = 5, x = - 3

\frac{1}{2} \cdot 3^{1}

e^{- 0.04} \cdot \frac{1.3 \cdot 35}{0.5}

s^{2} + 6 s + 34 = 0

\frac{x ^{- 1}}{x ^{- 8}}

- 9 + 6 x > - 15

What are the solutions to the equation 16-(x-1)^2=0 ?
The solutions to the equation 16-(x-1)^2=0 are x=5,x=-3
Find the zeros of 16-(x-1)^2=0
The zeros of 16-(x-1)^2=0 are x=5,x=-3